Simulation and modeling - Old Questions
Question Answer Details
11. Use the multiplicative congruential method to generate a sequence of four three-digit random numbers. Let X0=118, α=4 and m=1000.
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Official Answer
Given,
X0 = 118,
α = 4,
m=1000
We have,
For multiplicative congruential method:
Xi+1 = (α Xi ) mod m
& Ri =Xi/m,
The sequence of random numbers are calculated as follows:
X0 = 118
R0 = 118/1000 = 0.118
X1 = (α X0) mod m = (4*118) mod 1000 = 472 mod 1000 = 472
R1 = 472/1000 = 0.472
X2 = (α X1) mod m = (4*472) mod 1000 = 1888 mod 1000 = 888
R2 = 888/1000 = 0.888
X3 = (α X2) mod m = (4*888) mod 1000 = 3552 mod 1000 = 552
R3 = 552/1000 = 0.552
X4= (α X3 ) mod m = (4*552) mod 1000 = 2208 mod 1000 = 208
R4 = 208/1000 = 0.208
Therefore,
The sequence of random integers are 118, 472, 888, 552, 208.
The sequence of random numbers are 0.188, 0.472, 0.888, 0.552, 0.208.