Simulation and modeling - Old Questions

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11.  Use the multiplicative congruential method to generate a sequence of four three-digit random numbers. Let X0=118, α=4 and m=1000.

5 marks
Asked in 2069

Answer

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Official Answer

Given,

    X= 118

    α = 4,

    m=1000

We have,

For multiplicative congruential method:

        Xi+1 = (α X) mod m

        & R=Xi/m,

The sequence of random numbers are calculated as follows:

X= 118

R0 = 118/1000 = 0.118

X1 = (α X0) mod m = (4*118) mod 1000 = 472 mod 1000 = 472

R1 = 472/1000 = 0.472

X2 = (α X1) mod m = (4*472) mod 1000 = 1888 mod 1000 = 888

R2 = 888/1000 = 0.888

X3 = (α X2) mod m = (4*888) mod 1000 = 3552 mod 1000 = 552

R3 = 552/1000 = 0.552

X4(α X3 ) mod m = (4*552) mod 1000 = 2208 mod 1000 = 208

R= 208/1000 = 0.208

Therefore,
The sequence of random integers are 118, 472, 888, 552, 208.
The sequence of random numbers are 0.188, 0.472, 0.888, 0.552, 0.208.