Microprocessor and Computer Architecture 2080

Question Paper Details
Tribhuwan University
Institute of Science and Technology
2080
Bachelor Level / Second Semester / Science
Information Technology ( BIT151 )
( Microprocessor and Computer Architecture )
Full Marks: 60
Pass Marks: 24
Time: 3 hours hours

Section A

Long Answer Questions
Attempt any TWO questions. [2 × 10 = 20]

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1. What are Addressing Modes? Explain each with an example. Explain the function and type of addressing mode with the reason for the instruction STA 4000H. [10]

10 marks
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2. What is the control unit of a microprocessor? Draw the block diagram of the hardwired control unit and explain the function of each unit in brief. [10]

10 marks
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3. What is pipelining? Define instruction pipeline and explain the four-segment instruction pipeline. [10]

10 marks
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Section B

Short Answer Questions
Attempt any EIGHT questions. [8 × 5 = 40]

40 marks
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4. What is a Microprocessor? What are the three general categories of the function of a microprocessor? Explain in brief. [5]

5 marks
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5. Write an 8085 assembly language program to add two numbers located at 2030H and 2040H. Store the sum in the address 2050H. [5]

5 marks
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6. Design a 4-bit combinational circuit decrementer (A1 ← A1 - 1) using four full-adder circuits. Explain the circuit. [5]

5 marks
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7. What is the 'Selective Set' logical operation? Draw the hardware circuit of the 'Selective Set' logical operation. [5]

5 marks
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8. Show the step-by-step division process using the 'Restoring Division Algorithm' of 194 ÷ 10 (AQ = 10100011 by B = 1011). [5]

5 marks
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9. Explain the difference between isolated I/O and memory-mapped I/O. What are the advantages and disadvantages of each? [5]

5 marks
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10. What is Virtual Memory? Explain in brief. [5]

5 marks
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11. What do you understand by a microprogrammed control computer? Explain main memory and control memory of a microprogrammed controlled computer. [5]

5 marks
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12. Write short notes on:

  • a. Performance of a pipelined processor
  • b. Page Replacement
[2 × 2.5 = 5]
5 marks
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